/* Bismillahir Rahmanir Rahim
Solution using (MST)Kruskal's algorithm.
*/
#include<bits/stdc++.h>
#define fi(n, m) for(int i=n; i<=m; i++)
#define fd(n, m) for(int i=n; i>=m; i--)
using namespace std;
int pr[10001], n, m;
set<int>st;
struct edge{
int u, v, w;
}one[100001];
bool comp(edge f, edge s){
return f.w<s.w;
}
int find(int p){
if(pr[p]==p) return p;
else return find(pr[p]);
}
int mst(){
int sm=0, xx, yy, cnt=0;
fi(1, n) pr[i]=i;
fi(0, m-1){
xx=find(one[i].u);
yy=find(one[i].v);
if(xx!=yy){
pr[yy]=xx;
cnt++;
sm+=one[i].w;
}
if(cnt==n-1) return sm;
}
return sm;
}
int main(){
int t, c, cs=1, sz, ans, u, v, w, an;
cin>>t;
while(t--){
an=0;
cin>>n>>m>>c;
fi(0, m-1){
cin>>u>>v>>w;
if(w<c){
one[i].u=u;
one[i].v=v;
one[i].w=w;
}
else{ // special case
one[i].u=u;
one[i].v=u;
one[i].w=0;
}
}
sort(one, one+m, comp);
ans=mst();
fi(1, n){
st.insert(find(pr[i]));
}
sz=st.size();
cout<<"Case "<<cs++<<": "<<ans+(sz*c)<<" "<<sz<<endl;
st.clear();
}
return 0;
}
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Monday, February 20, 2017
Solution of Light OJ 1059 - Air Ports
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