Solution of Dev Skill DCP-1: Big Sum

See the problem  Big Sum

/* Bismillahir Rahmanir Rahim Problem-Logical. The following code is bulky in size but logic is simple. 456 789 ----- 1461 (its the answer)[add start from left to right] */ #include<bits/stdc++.h> using namespace std; int main(){ string s; while(cin>>s){ char s1[109], s2[109]; int i, temp, c=0, fl=0, sz1, sz2, y=0, x=0; for(i=0; i<s.size(); i++){ if(s[i]==',') fl=1; else if(!fl) s1[x++]=s[i]; // until getting ',' else s2[y++]=s[i]; // after getting ',' } fl=0; if(x>=y){ // if(first string >= second string) for(i=0; i<y; i++){ temp=(int)(s1[i]-'0')+(int)(s2[i]-'0')+c; if(temp==10){ if(fl)cout<<0; c=1; } else if(temp>10){ cout<<temp%10; c=1; fl=1; } else{ cout<<temp; c=0; fl=1; } } for(i=y; i<x; i++){ // after ending of second string temp=(int)(s1[i]-'0')+c; if(temp==10){ if(fl)cout<<0; c=1; } else if(temp>10){ cout<<temp%10; c=1; fl=1; } else{ cout<<temp; c=0; fl=1; } } } else{ // same as before, just replace y with x & x with y for(i=0; i<x; i++){ int temp=(int)(s1[i]-'0')+(int)(s2[i]-'0')+c; if(temp==10){ if(fl)cout<<0; c=1; } else if(temp>10){ cout<<temp%10; c=1; fl=1; } else{ cout<<temp; c=0; fl=1; } } for(i=x; i<y; i++){ temp=(int)(s2[i]-'0')+c; if(temp==10){ if(fl)cout<<0; c=1; } else if(temp>10){ cout<<temp%10; c=1; fl=1; } else{ cout<<temp; c=0; fl=1; } } } if(c) cout<<c%10; cout<<endl; } return 0; }